What is the nuclear binding energy for uranium-238 in joules

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The correct answer is (C) 2.8807 x 10^-10

Explanation:

According to this formula:

E = MC^2

when E is the nuclear binding energy

and M is the mass defect = 3.2008 x 10^-27 Kg

and C is the speed of light = 3 x 10^8 m/s^2

so, by substitution:

∴ E = 3.2008 x 10^-27 * (3 x 10^8 )^2

= 2.8807 x 10^-10

a electromagnetic waves

the small 0.38-kg slider is known to move from position a to position b along the vertical-plane slot. determine (a) the work done on the body by its weight and (b) the work done on the body by the spring. the distance r = 0.70 m, the spring modulus k = 154 n/m, and the unstretched length of the spring is 0.53 m

explanation:

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