Amodel electric train requires 3.7267 v to operate. if the primary coil of its transformer has 184.463 turns windings, how many windings should the secondary have if the primary is connected to a 100.864 v household circuit? answer in units of turns.

= 6.815 turns

Explanation:

From the Turn ratio equation;

Ns/Np= Vs/Vp

Where; Ns and Np is the number of turns in the secondary and primary coil respectively.

Vs and Vp are the voltages in the secondary and primary coils respectively.

Since; Vs = 3.7267 V, Vp = 100.864 V, Ns =?  and Np =184.463 turns

Thus;

Ns = (Np× Vs)/Vp

     =(184.463×3.7267)/100.864

     = 6.815 turns

Therefore, the number of windings in the secondary coil should be 6.815 turns.

b

step-by-step explanation: a third of 24 is 8, 8 times 3 is 24 so 8 - 2 would be 6