Find the height of a baseball with a mass of 0.15 kg that has a gpe of 73.5 j.

?

Gravitational Potential Energy of an object, relative to the ground =

           (mass) x (acceleration of gravity) x (height above the ground)

               73.5 J  =  (0.15 kg)  x  (9.8 m/s²)  x  (height above the ground).

1 J = 1 kg · m² / s²

               73.5 kg·m²/s²  =  (0.15 kg) · (9.8 m/s²) · (height)

Divide each side by (0.15 kg): 

               (73.5 kg·m² / (0.15 kg·s²)      = (9.8 m/s²) · (height)

Divide each side by (9.8 m/s²):

               (73.5 kg·m²·s²) / (0.15 kg·s² · 9.8 m)  =  (height)

After doing all the arithmetic on the left side:

               (73.5) / (0.15 · 9.8) (m)   =   height

                       50                 (m)    =   height

Ithink the answer is a

The law of conservation of momentum will be the same no matter where you apply it.the equation will be  77.4 + m (mass of canister) *3.6