Will give brainliest answer, 5 stars, and

an ice skater with a moment of inertia (i) equal to 1.56 kg m2 is spinning with an angular velocity of 11 radians/sec.
if the ice skater increases his moment of inertia by lifting his arms out to the side to 3.12 kg m2 , what will the new angular velocity be?

a) 5.5 radians/s

b) 22 radians/s

c) 11 radians/s

b 22 radians/s and I hope it work for you

The answer is C. 5.5 radians

Explanation:Just did the math. Hope this helps!!

initial speed when it is dropped is 150 ft/s

now at the same moment the acceleration due to gravity is perpendicular to its velocity

so as we know that

now we have centripetal acceleration a = 32 ft/s^2 as its perpendicular to velocity

while tangential acceleration at the same moment will be zero

so

now radius of curvature is given as

so the radius of curvature just after it is dropped is 703.125 ft