An air-track glider attached to a spring oscillates between the 15.0 cm mark and the 68.0 cm mark on the track. the glider completes 7.00 oscillations in 31.0 s . what is the period of the oscillations?

4.42 s

Explanation:

The frequency of the oscillation is given by the ratio between the number of complete oscillations and the time taken:

where for this glider, we have

N = 7.00

t = 31.0 s

Substituting, we find

Now we now that the period of oscillation is the reciprocal of the frequency:

So, substituting f = 0.226 Hz, we find:

c) up is the direction the magnetic force is acting on the charge.

we have been given a quadratic function and we need to restrict the domain such that it becomes a one to one function.

we know that vertex of this quadratic function occurs at (5,2).

further, we know that range of this function is .

if we restrict the domain of this function to either or , it will become one to one function.

let us know find its inverse.

upon interchanging x and y, we get:

let us now solve this function for y.

hence, the inverse function would be if we restrict the domain of original function to and the inverse function would be if we restrict the domain to .