Adrunk guy walking on a narrow lane takes 8 steps forward and 6 steps backward and so on.
each step is 1m long and he requires 1 second to travel. the time that the drunk guy takes to fall in a pit 18m away from the starting point is

a) 18s
b) 126s
c) 78s
d) 62s

Answer: it will take   4.36 seconds to reach her average velocity 10.69 miles/hour.explanation:   we have equation of motion ,where s is the displacement, a is the acceleration, u is the initial velocity and t is the time taken.average velocity = displacement/ time taken.average velocity = 10.69 miles/hr = 10.69*1.6*1000/(60*60) = 4.75 m/s4.75 = s/ts = 4. 1we also have acceleration = 2.18 m/s², initial velocity = 0 m/sso it will take   4.36 seconds to reach her average velocity 10.69 miles/hour.