Arunner moves 2.88 m/s north. she accelerates at 0.350 m/s^2 at a -52.0 angle. at the point in the motion where she is running directly east, what is î”x?

The runner has initial velocity vector

and acceleration vector

so that her velocity at time is

She runs directly east when the vertical component of is 0:

It's not clear what you're supposed to find at this particular time... possibly her position vector? In that case, assuming she starts at the origin, her position at time would be

so that after 10.4 s, her position would be

which is 19.9 m away from her starting position.

a cold ice-tea.

pour in room temperature or cold water. cover the pitcher and refrigerate. steep white or green tea for 6 to 8 hours; steep black or oolong tea for 8 to 12 hours.jun 28, 2015

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