Suri rolled a bowling ball down a lane in 2.5 s. the ball traveled
at a constant acceleration of 1.8 m/s/s down the lane and was
traveling at a speed of 7.6 m/s by the time it reached the pins at
the end of the lane. how fast was the ball going at the
beginning, when it left suri's hand?

3.1 m/s

Explanation:

The acceleration of the ball is given by:

where

v is the final velocity

u is the initial velocity

t is the time elapsed

Here we know:

a = 1.8 m/s^2 is the acceleration

v = 7.6 m/s is the final velocity

t = 2.5 is the time elapsed

Solving for u, we find the initial velocity of the ball:

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