Amissile is fired from a jet flying horizontally at mach 2 (2200 ft/s). the missile has a horizontal acceleration of 1000 ft/s2. calculate its horizontal velocity at 10.0 seconds after it is fired. (assume constant acceleration of the missile throughout its flight.) 12,200 ft/s 10,000 ft/s 2300 ft/s 7800 ft/s

12200 ft/s

Explanation:

The question is on constant acceleration

→Uniform acceleration motion is given by⇒⇒⇒     Vf=Vo+ at(a)

→Where Vf= final velocity=?

            Vo=initial velocity =2200 ft/s

              a= acceleration= 1000ft/s²

               t= 10.0 sec

Substitute values in (a) above

Vf=Vo+ at

Vf= 2200 + ( 1000×10) = 12200 ft/s