Agirl and a boy are riding on a merry go round that is turning at a constant rate. the girl is near the outer edge, and the boy is closer to the center. who has greater tangential acceleration? both the girl and boy have the same nonzero tangential accelerationthe boy has greater tangential accelerationboth the girl and the boy have zero tangential accelerationthe girl has greater tangential acceleration

The girl has greater tangential acceleration

Explanation:

The angular acceleration () of the merry go round is equal to the rate of the change of the angular velocity, :

Since all the points of the merry go round complete 1 circle in the same time, the angular velocity of each point of the merry go round is the same, and so all the points also have the same angular acceleration.

The tangential acceleration instead is given by

where

is the angular acceleration

r is the distance from the centre of the merry go round

Since the girl is near the outer edge and the boy is closer to the centre, the value of r for the girl is larger than for the boy, so the girl has greater tangential acceleration.

1 the 4 is sig

weight of the box is given as

here this is placed on the inclined of angle 42 degree

now this weight will have two components one is along the incline other is perpendicular to it

so here we need to apply a force parallel to incline opposite to its component of weight

so here the component of weight is given as

here we have

so it requires 75 n force to move it upwards