Aspherical capacitor contains a charge of 3.10 nc when connected to a potential difference of 250 v. if its plates are separated by vacuum and the inner radius of the outer shell is 4.00 cma)calculate the capacitance: found to be 1.24*10^-11 fb)find the radius of the inner spere: found to be .0294mc)calculate the electric field just outside the surface of the inner sphere. t

(a)

The general formula for the capacitance of a capacitor is:

where

Q is the charge stored on the capacitor

V is the potential difference across the capacitor

In this problem, we have

is the charge stored

V = 250 V is the potential difference

Substituting, we find

(b) 0.0294 m

The capacitance of a spherical capacitor is given by

where

a is the radius of the inner shell

b is the radius of the outer shell

Here we have

b = 4.00 cm = 0.04 m

and the capacitance is

So we can re-arrange the equation to find a, the radius of the inner sphere:

(c)

The electric field just outside the surface of the inner sphere with charge Q is equal to the electric field produced by a single point charge Q at a distance of r = a:

where

is the charge on the sphere

a = 0.0294 m is the radius of the inner sphere

Substituting the data into the formula, we find:

answer: the metamorphic rocks are formed when they are exposed to high pressure and high temperatures. this happens when one of the earth's plates comes in contact with the other plate by traveling in opposite directions, straight into each other or slipping under one another. the friction that is caused by this activity results in   melting of rocks and when it cools they are known as metamorphic rocks. this process needs a controlled amount of pressure and temperature otherwise it may turn into magma.

i believe the answer is a hope it and is correct