Its timed hurry the voltage across the primary winding is 350,000 v, and the voltage across the secondary winding is 17,500 v. if the secondary winding has 600 coils, how many coils are in the primary winding? a. 30 coils b. 583 coils c. 12,000 coils d. 332,500 coils

12,000 coils. The primary winding has 12,000 coils.

In order to solve this problem we have to use the relation for a transformer Vp/Vs = Np/Ns, where Vp is the voltage across the primary winding, Vs in the voltage across the secondary winding, Np is the numbers of coils in the primary winding, and Ns is the number of coils en the secondary winding.

With Vp = 350,000 V, Vs = 17,500 V, and Ns = 600 coils:

350,000 V/17,500 = Np / 600 coils

Np = (600 coils x 350,000 V) / 17,500 V

Np = 210,000,000/ 17,500 coils

Np = 12,000 coils