The triceps muscle in the back of the upper arm extends the forearm. this muscle in a professional boxer exerts a force of 2.00 x 10^3 n with an effective perpendicular lever arm of 3.10 cm, producing an angular acceleration of the forearm of 125 rad/s2. what is the moment of inertia of the boxer's forearm? kg · m2

Explanation:

The torque exerted is given by

where

is the force applied

d = 3.10 cm = 0.031 m is the length of the lever arm

Substituting,

The equivalent of Newton's second law for rotational motion is:

where

is the net torque

I is the moment of inertia

is the angular acceleration

Solving the equation for I, we find

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