Will give brainliest answer a stunt person runs off the empire state building at a horizontal speed of 12.5 m/s. according to the diagram where will he land? a) location a (in the street) b) location b (on the brown building before the pool) c) location c (in the rooftop pool)

-- The roof of the brown building is (381 - 281) = 100 meters lower than the roof he runs horizontally off of.

-- How long will it take him to fall to the level of the roof of the brown building ?

D = (1/2) (g) (T²)

100 m = (1/2) (9.8 m/s²) (T²)

100 m = (4.9 m/s²) (T²)

T = √(100/4.9) seconds

T = 4.52 seconds

-- During that amount of time, the guy will move

(12.5 m/s) x (4.52 sec)  =  56.47 meters horizontally

-- But the edge of the brown building is only 55 meters away from where he jumped.

-- So when he reaches the edge of the brown building, he'll still be above its roof.  He will sail another (56.47 - 55) = 1.47 meters above the roof of the brown building before he falls down onto it.

-- He will land in Area-B on the brown building, at a spot that's

(20 - 1.47) = 18.53 meters short of the edge of the pool.  (Choice-B)

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