Consider an electric motor with a shaft power output of 22.5 kw and an efficiency of 85%. determine the rate at which the motor dissipates heat to the room it is in when the motor operates at full load. in winter, this room is normally heated by a 2.5 kw resistance heater. determine if it is necessary to turn the heater on when the motor runs at full load

lower, it's not as dense as chocolate syrup.

choco syrup is more like a solid than a liquid and even turns solid if it gets slightly cold,

orange juice however is a 95% liquid and has a very low viscosity

answer; equivalent to a one(1) horsepower motor;

electrical potential energy =0.072 j

explanation:

electrical potential energy is given by

u= q δv

q= charge=6 c

δv= potential difference and is given by

δv= e d

e= electric field

d= distance=5 mm=0.005 m

δv=2.4 (0.005)=0.012 v

now electric potential energy= u= q δv

u=6 (0.012)

u=0.072 j