Abus starts to move from rest. if it's velocity becomes 90 km per hour after 8 seconds , calculate it's acceleration (numerical problem)

Assuming the bus undergoes constant acceleration, it is given by:

a = (Vf-Vi)/Δt

a is the acceleration, Vf is the final velocity, Vi is the initial velocity, and Δt is the elapsed time.

Given values:

Vf = 90km/hr = 25m/s (the conversion rate from km/hr to m/s is 1/3.6)

Vi = 0m/s (starts from rest)

Δt = 8.0s

Plug in the values and solve for a:

a = (25-0)/8

a = 3.125m/s²

Round to 2 significant figures.

a = 3.1m/s²

a charge 3q is at the origin, and a charge −2q is on the positive x axis at x=a. part a where on the x-axis would you place a third charge so it would experience no net electric force? enter an expression for the exact answer, which will involve a square-root sign. (do not enter an approximate decimal answer.)

it is called kinetic energy