A2.0-kg ball moving eastward at 3.0 m/s suddenly collides with and sticks to a 4.0-kg ball moving northward at 2.0 m/s. what is the magnitude of the momentum of this system just after the collision?

10 kg m/s

Explanation:

According to the law of conservation of momentum, the total momentum before the collision must be equal to the total momentum after the collision. So, we can simply calculate the total momentum before the collision.

The two balls are moving in perpendicular directions - one eastward and one northward. If we take eastward as positive x-direction and northward as positive y-direction, this means that we can find the magnitude of the total momentum by simply using Pythagorean theorem.

The magnitude of the momentum of the ball travelling eastward is:

The magnitude of the momentum of the ball travelling northward is:

So the magnitude of the total momentum is:

c. rb

explanation:

the atomic radius of a chemical element is a measure of the size of its atoms, usually the mean or typical distance from the center of the nucleus to the boundary of the surrounding shells of electrons.

i think it because equal matrices have equal dimensions, only square matrices can be symmetric. for all indices and . every square diagonal matrix is symmetric, since all off-diagonal elements are zero. in linear algebra, a real symmetric matrix represents a self-adjoint operator over a real inner product space.