Consider a particle with initial velocity v⃗ that has magnitude 12.0 m/s and is directed 60.0 degrees above the negative x axis. 1.what is the x component vx of v⃗ ? 2.what is the y component vy of v⃗ ?

The change of displacement with respect to time is defined as the velocity. The x component of the velocity will be -6.0 m/sec. while the velocity in the y-direction will be 10.4 m/sec.

The change of displacement with respect to time is defined as the velocity.

velocity is a vector quantity. it is a time-based component. Velocity at any angle is resolved to get its component of x and y-direction.

= angle measured from the positive x-axis

In the above conditions, the angle is given from the - ve x-axis is 60 degrees. If it is measured from the + ve x-axis it will be 180- 60= 120 degrees.

Given velocity v = 12.0 m/sec

= -6.0 m/sec

= 10.4 m/sec

Hence the x component of the velocity will be -6.0 m/sec. while the velocity in the y-direction will be 10.4 m/sec.

To learn more about the velocity refer to the link ;

link

-6.0 m/s, 10.4 m/s

Explanation:

To find the x- and y- components, we have to apply the formulas:

where

v = 12.0 m/s is the magnitude of the vector

is the angle between the direction of the vector and the positive x-axis

Here, the angle given is the angle above the negative x-axis; this means that the angle with respect to the positive x-axis is

So, the two components are:

trig 15.3 cos