Asmall bouncy ball with a momentum of 8 kg∙m/s to the left approaches head-on a large door at rest. the ball bounces straight back with a momentum of 6 kg∙m/s. what is the change in the momentum of the ball? what is the impulse exerted on the ball? what is the impulse exerted on the door?

-14 kg m/s

Explanation:

Taking the  direction "to the left" as positive direction, the initial momentum of the ball is

p1 = +8 kg m/s

while the final momentum is

p2 = -6 kg m/s

so the change in momentum is

According to the impulse theorem, the impulse exerted on the ball is equal to the change in momentum of the ball, so:

(which means 14 kg m/s to the right)

While the impulse that the ball exerted on the ball is equal and opposite in direction, so:

(which means towards the left)

i believe the answer is electric potential.

explanation:

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