The very top of the film shows no reflected light, indicating that the thickness is less than 1/4 the wavelength of visible light within the film, since the phase change on reflection for the beam from the first surface of the film is π radians and the phase change on reflection from the second surface of the film is 0 radians, making the interfering rays mostly out of phase from that part of the film. given this information, what is the approximate thickness of the film at the first bright fringe counting from the top of the film, in terms of the wavelength of light in vacuum λ, and the refractive index of the film n?

To understand the behavior of the electric field at the surface of a conductor, and its relationship to surface charge on the conductor. a conductor is placed in an external electrostatic field. the external field is uniform before the conductor is placed within it. the conductor is completely isolated from any source of current or charge. part a: which of the following describes the electric field inside this conductor? it is in the same direction as the original external field.it is in the opposite direction from that of the original external field.it has a direction determined entirely by the charge on its surface.it is always zero. part b: the charge density inside the conductor is: 0non-zero; but uniformnon-zero; non-uniforminfinite part c: assume that at some point just outside the surface of the conductor, the electric field has magnitude e and is directed toward the surface of the conductor. what is the charge density η on the surface of the conductor at that point? express your answer in terms of e and ϵ0

The particles that are found in the nucleus of an atom are

Me with this and you will be marked brainliest