Asmall object has a mass of 3.0 × 10-3 kg and a charge of -32c. it is placed at a certain spot where there is an electric field. when released, the object experiences an acceleration of 2.4 × 103 m/s2 in the direction of the +x axis. determine the electric field, including sign, relative to the +x axis.

-0.0225 N/C

Explanation:

First of all, we can calculate the force exerted on the object, which is given by:

F = ma

where

is the mass

is the acceleration

Substituting,

and the direction is the same as the acceleration (+x axis).

Now the electric force is given by

where

is the charge

E is the electric field

Solving for E, we find

and the negative sign means the direction is -x axis.

true

explanation: