Abeam of electrons moves at right angles to a magnetic field of 4.5 × 10-2 tesla. if the electrons have a velocity of 6.5 × 106 meters/second, what is the force acting on the electrons? the value of q = -1.6 × 10-19 coulombs.

Explanation:

For a charge moving perpendicularly to a magnetic field, the force experienced by the charge is given by:

where

q is the magnitude of the charge

v is the velocity

B is the magnetic field strength

In this problem,

So the force experienced by the electrons is

fgravity=10x10=100n case 1

fgravity=30x20=600n case 2

6 times more

find the surface area of the sphere to the nearest square unit. use a calculator.

a. 254 in.2

b. 64 in.2

c. 127 in.2

d. 1,018 in.2