Afrequency generator sends a 550 hz sound wave through both water and ice. what is the difference in wavelength between the wave produced in ice and the wave produced in water?

Δλ =  3.103 m.

To solve this problem we have to know the speed of sound in both elements water and ice.

Element            Speed of sound

Water (25°C)           1493 m/s

Ice                           3200 m/s

The velocity of a wave is given by the equation v = λf, where λ is the wavelength, and f is the frecuency of the wave.

In order to calculate the wavelength we have to clear λ in the equation v = λf, resulting:

λ = v/f

Calculating the wavelength in both elements:

λ(water) = 1493 m/s / 550 Hz = 2.715 m

λ(ice) = 3200 m/s / 550 Hz = 5.818 m

So, the difference in wavelength between the wave produced in ice and the wave produced in water is:

Δλ = λ(water) - λ(ice) = 5.818 m - 2.715 m

Δλ =  3.103 m

float.

archimedes' principle

denser than water sinks in water.

denser than mercury would sink in it