The edge of a flying disc with a radius of 0.13 m spins with a tangential speed of 3.3 m/s. the centripetal acceleration of the edge of the disc is m/s2

Explanation:

The centripetal acceleration is defined as the square of the tangential velocity between the radius.

In this case we know that the radius r is

The speed v is:

Then we use these values to find the centripetal acceleration.

Is going to be (84)

Explanation:

The correct answer is

D. 84

Explanation:

The centripetal acceleration of the edge of the disc is given by:

where

v=3.3 m/s is the tangential speed at the edge of the disc

r=0.13 m is the radius of the disc

Therefore, substituting the numbers into the equation, we find the centripetal acceleration: