Physics, 22.06.2019 02:30 estrellagutierrez12

Which type of bond is found between the atoms of a molecule? a. metallic b. delocalized electron c. covalent d. ionic

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Answer from: grantjaylynn

Hello There!

The type of bond that is found between the atoms of a molecule is called "COVALENT" bond.

A covalent bond is where two atoms share a pair of electrons.

Answer from: rosemarybooker

The bond between the atoms of molecule is Covalent bond.

Option C

Explanation:

Covalent bond due to its phenomenal activity is also known as molecular bond. The electron pairs are shared between the atoms, these shared electron pairs are known as "shared pairs or bonding pairs".

This type of covalent bonding establishes balance between the atoms against attractive and repulsive forces. Covalent bonds are more common than ionic bonds.

Answer from: Quest

change tension

Answer from: Quest

russian is not my first language, so i'm afraid i can't write out an answer in russian, but hopefully you can find a way to do so. here's my best translation of the problem: you're given a plot of a particle's position in one-dimensional space over time, and you're asked to find either the total distance traveled by the particle after 6 seconds had elapsed, or the total displacement of the particle after 6 seconds.

if you want the total distance traveled, you would first need to determine the particle's velocity as a function of time, then integrate that over the 6-second interval. we know the position function is quadratic with roots at 0 and 6, so we have

$x(t)=ax(x-6)$

where $a$ is unknown. because the position is parabolic, there is symmetry about the midpoint at $t=3$ , and we know that

$x(3)=10\implies -9a=10\implies a=-\dfrac{10}9$

so that the position function is

$x(t)=-\dfrac{10}9x(x-6)$

which means the velocity is

$v(t)=\dfrac{\mathrm dx}{\mathrm dt}=-\dfrac{20}9x+\dfrac{60}9$

then the total distance traveled is

$\displaystyle\int_{t=0}^{t=6}|v(t)|\,\mathrm dt=\left\{\int_{t-0}^{t=3}-\int_{t=3}^{t=6}\right\}v(t)\,\mathrm dt=20$

so the total distance traveled is 20 m.

on the other hand, if you want to find displacement: the particle starts at $x=0$ and ends at $x=0$ , so its displacement is 0.

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