Formula one race cars are capable of remarkable accelerations when speeding up, slowing down, and turning corners. at one track, cars round a corner that is a segment of a circle of radius 95 m at a speed of 68 m/s. what is the approximate magnitude of the centripetal acceleration, in units of g?

Centripetal acceleration of the car is (4.96 g) m/s²

Explanation:

It is given that,

Radius of circle, r = 95 m

Speed of the car, v = 68 m/s

We need to find the centripetal acceleration. It is given by :

So,

Since, g = 9.8 m/s²

So,

So, the magnitude of the centripetal acceleration is (4.96 g) m/s². Hence, this is the required solution.

air exerts forces on falling objects near earth’s surface.

explanation:

the term 'free falls' refer to object that are falling towards the earth, in a situation in which gravity is the only force acting on the object.

for an object in free fall, the acceleration is constant (g, the gravitational acceleration), and so the velocity of the object constantly increases.

for objects near earth's surface, there is always another force acting on the object: the resistance due to the air. this force is opposed to the direction of fall of the object, and it is proportional to the velocity of the object, so as the object falls down, this force increases up to a point when it balances the force of gravity, and the object continues its motion at constant velocity (called terminal velocity). since in this case gravity is not the only force acting on the object, we are not in a situation of free fall.