Acar is traveling at 50 mi/h when the brakes are fully applied, producing a constant deceleration of 44 ft/s2. what is the distance covered before the car comes to a stop? (round your answer to one decimal place.) ft

The distance covered by car before stopping is 61.13 ft.

Explanation:

Given data:

Initial Speed of car is, .

Deceleration of car is, . (Negative sign shows negative acceleration)

Applying the second kinematic equation of motion as,

Here, s is the distance covered and v is the final speed. Since, car stops finally, v = 0.

Solving as,

Thus, distance covered by car before stopping is 61.1 ft.

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Distance, d = 61.13 ft

Explanation:

It is given that,

Initial speed of the car, u = 50 mi/h = 73.34 ft/s

Finally, it stops i.e. v = 0

Deceleration of the car,

We need to find the distance covered before the car comes to a stop. Let the distance is s. It can be calculated using third law of motion as :

s = 61.13 ft

So, the distance covered by the car before it comes to rest is 61.13 ft. Hence, this is the required solution.

what experimental evidence led scientists to change from the previous model to this one?

a few of the positive particles aimed at a gold foil seemed to bounce back.

the colors of light emitted from heated atoms had very specific energies.

experiments with water vapor showed that elements combine in specific proportions.

cathode rays were bent in the same way whenever a magnet was brought near them.