Acircuit consists of a power supply and two resistors r1 and r2 connected in parallel. an ammeter is placed to measure the current through the restive r1. the ammeter reads i1= 7.7ma and the values of the resistors are r1=6.0 k ohm and r2= 1.6 ohm. the power supply was turned off, then the circuit was modified. resistor r1 was replaced with a different resistor rnew= 1.2 ohm. the power supply is turned back on. it provides exactly the same voltage as originally. what is the new current through resistor rnew?

W= fd
where f is an applied force and d is the distance over which it is applied. when a parachuting skydiver is at constant velocity, he is experiencing "terminal velocity", the point at which his acceleration down is canceled out by air resistance. that means that the resisting force of the air is equal to his weight, but in the opposite direction. with this, we can solve for the work done by the force.
w = fd
w = (92.0)(9.81 m/s^2) (325)
w= 2.93 x 10^5 j
the value for work in this case is positive because it is pushing up on the skydiver, who has a downward force of gravity.
therefore the answer is 2.93 x 10^5 j