What is the final velocity of a 28 kg object that has an initial velocity of 5 m/s and has a force of 232 n exerted on in for 5.2 seconds? do not leave a space between the units and the answer. no decimals-round to nearest whole number.

48 m/s

Explanation:

m = mass of the object = 28 kg

F = magnitude of net force acting on the object = 232 N

acceleration of the object is given as

a = F/m

a = 232/28

a = 8.3 m/s²

v₀ = initial velocity of the object = 5 m/s

v = final velocity of the object

t = time interval = 5.2 s

using the kinematics equation

v = v₀ + a t

v = 5 + (8.3) (5.2)

v = 48 m/s

this is an example of "committed" time.

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