What is the speed of an indestructible person standing on the equator of the collapsed star? (neglect any relativistic or thermal effects, and assume the star is spherical before and after it collapses).

force is mass*acceleration.

we have a very small mass: 11.4*0.001 kg

if we want 0.035n of force, we need an acceleration:

0.035 = 11.4*0.001*a

a = 0.035/(11.4*0.001) m/s^2

t = 1/400 h   ⇔ 0.0025 h ⇔ 9s ⇔ 0.15 m

any of the answers are correct.