Asample of blood is placed in a centrifuge of radius 12.0 cm. the mass of a red blood cell is 3.0 ✕ 10^−16 kg, and the magnitude of the force acting on it as it settles out of the plasma is 4.0 ✕ 10^−11 n. at how many revolutions per second should the centrifuge be operated?

167.85 rev / s

Explanation:

r = 12 cm = 0.12 m, m = 3 x 10^-16 kg, F = 4 x 10^-11 N

F = m r w^2

where, w is the angular velocity.

4 x 10^-11 = 3 x 10^-16 x 0.12 x w^2

w = 1054.1 rad / s

w = 2 π f

f = w / 2 π = 1054.1 / (2 x 3.14) = 167.85 rev / s

f=ma newton

f=100x2.5=250n

overcharge is the right answer system