Iron has a bcc structure with a lattice constant a: 2.86 a a) using the value of the saturation magnetization in table 9.6, show that the dipole moment of an fe atom is equal to 2.22 ub. the density of fe is 1.92 g/cm', and its atomic weight is 55.6. (you may assume, for the present purpose, that the 3d electrons are completely localized.) b) calculate the weiss exchange constant λ and the molecular field in iron c) evaluate the curie constant in iron d) estimate the exchange energy for a dipole interacting with its nearest neighbors. curic temperature and saturation magnetizations for ferromagnetic substancesf ( is the number of magnetons per unit at 0 k) substance t. k m, at 0°k , at 0 k 1.74 × 106 amp-m 1.45 0.5 2.01 2.92 fe co 1043 1403 631 289 105 515 410 480 130 2.22 1.72 0.54 7.10 10.1 gd cro2 mnofe203 feofe203 y fe o12(yig) 2.03 5.0 5.0 0.2

Answer: a charge of -1.0  × 10⁻⁴ c must be placed  at x = 26 m.the sign of the charge will be the same sign as the  -4.0  µc charge.======electricstatic force between two point charges  is given by    where k is coulomb's constant,  8.99×10⁹  n·m²/c², q₁ and q₂ are the point charges, and r is the distance between the two point charges.assign positive to q₁let q₁ =  6.0 µc, q₂ = -4.0  µc, q₀ represent the charge at the origin, and q₃ represent this new charge to place.the charge at the origin q₀ would experience the following force f₀₁ from q₁, with r = 6.0 m (note that 1  µc = 10⁻⁶ c)    the force from q₂    the force from q₃    the net force on the origin charge, q₀, has to be zero for no electrostatic forcehaving an equation where k and q₀ can be divided out of the equation will allow us to solve for q₃    isolating:     a charge of -1.0  × 10⁻⁴ c must be placed  at x = 26 m.the sign of the charge will be the same as the  -4.0  µc charge

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Well i am not very good at this but  i would be guessing 1hope i