Because the centripetal force is provided by spring for this apparatus, the centripetal force at a given distance r is fixed by the spring constant of the spring. therefore, mv^2 should be constant for a given radius r. calculate the quantity mv^2 for the four data points taken at the same radius r. describe the agreement of those values.
there were only 3 data points: 0.43825, 0.48825, and 0.53825 and the mv^2 were calculated for each which i have written below the question in the picture for each of the three data points (1.30, 1.27, and 1.40). what is the agreement of these values?

The inside surface of a cylindrical-shaped cave of inner diameter 1.0 m is continuously covered with a very thin layer of water. the cave is very long and it is open on both ends. the water on the cave surface is at a constant temperature of 15.5 °c. the cave is constantly exposed to wind such that 15.5 °c air flows through the cave at 4.5 m/s. the kinematic viscosity of the air is 14.66 x 10-6 m2/s and the molecular diffusion coefficient of water vapor in the air is 0.239 x 10-4 m2/s. because the cave diameter is so large, the flow of wind down the length of the cave, in the x direction, can be treated like it is external flow and the cave surface can be approximated as flat where appropriate. calculate the x value, in a) the transition to turbulent flow occurs at rex meters, where the air flow transitions from laminar to turbulent along the inside surface of the cave b) calculate the x value, in meters, where the bulk steady state concentration of water vapor in the air flowing in the cave is 10% of the saturation concentration. assume the air at the surface of the water layer is 100% saturated with water vapor. assume the wind entering the cave contained no moisture before it entered the cave. take into account the transition from laminar to turbulent flow when solving part b