Asolenoid of length 0.700 m having a circular cross-section of radius 5.00 cm stores 6.00 µj of energy when a 0.400-a current runs through it. what is the winding density of the solenoid? (μ 0 = 4π × 10-7 t · m/a)

N/l = 104

Explanation:

Energy stored in the inductor is given by the formula

now we have

now we have

now we have

now winding density is turns per unit length

a displacement distance is size of displ

can be answered using momentum.

momentum = p

p1= mass1 * velocity1

p1 = p2

therefore

p1 = 6kg * 4m/s

p1 = 24kgm/s

p2=m2 * v2

24 kgm/s = 7kg * v2

v2 = 24 kgm/s / 7kg

v2= 3.42 m/s