Apendulum is made by letting a 2.0-kg object swing at the end of a string that has a length of 1.5 m. the maximum angle the string makes with the vertical as the pendulum swings is 30°. what is the speed of the object at the lowest point in its trajectory?

v = 2 m/s

Explanation:

Here we can use energy conservation to find the speed at the lowest point on its trajectory

As we know that by energy conservation

initial total gravitational potential energy = final total kinetic energy

now the height that is moved by the pendulum while it swing down is given as

now we can use energy conservation as

v = 1.978 m/s

Explanation:

Given that,

Mass of the object, m = 2 kg

Length of the string, l = 1.5 m

The maximum angle the string makes with the vertical as the pendulum swings is 30°,

The pendulum have gravitational potential energy when the angle is maximum. The pendulum has only kinetic energy at its lowest point. Let v is the speed of the object at the lowest point in its trajectory. It can be calculated as :

h is the height moved by the pendulum.

h = 0.2 m

v = 1.978 m/s

So, the speed of the object at the lowest point in its trajectory is 1.978 m/s.

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answer( sicar );