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An opposite a positive charge qi = +1 cm, y2 0. for q = 2.00 c: charge q2 -q is at x2 a (30%) show in a vector diagram the direction of the net electric field e at the point p located at x = 2.00 cm, y = 1.00 cm find the distances and directions needed to calculate e. b (70%) find the magnitude of e at that point 6 2 x10 y -6 p 1 2 p m -c
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