Auniform thin rod is hung vertically from one end and set into small amplitude oscillation. if the rod has a length of 3.6 m, this rod will have the same period as a simple pendulum of length cm. round your answer to the nearest whole number.

The length of the simple pendulum is 2.4 meters.

Explanation:

Time period of simple pendulum is given by :

L is the length of pendulum

The time period of the rope is given by :

L' is the length of the rod, L' = 3.6 m

It is given that, the rod have the same period as a simple pendulum and we need to find the length of simple pendulum i.e.

On solving the above equation as :

L = 2.4 m

So, the length of the thin rod that is hung vertically from one end and set into small amplitude oscillation 2.4 meters. Hence, this is the required solution.

acceleration = (change in speed) / (time for the change)

change in speed = (20-120)= -100 m/s.

1.5 min = 90 sec

acceleration = -100/90 = -1.11 m/s^2.

we don't care about the 150kg or the 2,500 meters. they don't make any difference.

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