The maximum wavelength for photoelectric emission in tungsten is 230 nm. what wavelength of light must be used inorder for electrons with a maximum energy of 1.5 ev to be ejected ?

180.04 nm

Explanation:

λ₀ = maximum wavelength for photoelectric emission in tungsten = 230 x 10⁻⁹ m

E₀ = maximum energy of ejected electron = 1.5 eV = 1.5 x 1.6 x 10⁻¹⁹ J

λ = wavelength of light used = ?

Using conservation of energy

Energy of the light used = Maximum energy required for photoelectric emission + Energy of ejected electron

λ = 180.04 x 10⁻⁹ m

λ = 180.04 nm