Acurrent of 0.2 a flows through a 3 m long wire that is perpendicular to a 0.3 t magnetic field. what is the magnitude of the force on the wire in units of newtons?

Magnetic force, F =  0.18 N

Explanation:

It is given that,

Current flowing in the wire, I = 0.2 A

Length of the wire, L = 3 m

Magnetic field, B = 0.3 T

It is placed perpendicular to the magnetic field. We need to find the magnitude of force on the wire. It is given by :

F = 0.18 N

So, the magnitude of force on the wire is 0.18 N. Hence, this is the required solution.

compass can be used day and night, cloudy or sunny

  distance on the y-axis and time on the x-axis.

explanation:

the instantaneous velocity = change in position/time taken

the slope of the graph should give instantaneous velocity.

  slope of a graph = change in value of y -axis / change in values of x -axis

  comparing both the equations

    change in value of y -axis = change in position

  change in values of x -axis = time taken

so position values should be on the y axis and time values should be on the x axis.

distance on the y-axis and time on the x-axis.