How much energy is stored by the electric field between two square plates, 8.5 cm on a side, separated by a 2.5-mm air gap? the charges on the plates are equal and opposite and of magnitude 14 nc .

The stored energy is .

Explanation:

Given that,

One side of square plates = 8.5 cm

Distance = 2.5 mm

Charge = 14 nC

We need to calculate the energy stored

The energy is stored by the electric field between two square plates is defined as,

We calculate the area iof square plates

Now, put the value into the formula

Hence, The stored energy is .

The quantity of energy that is stored by the electric field between two square plates is

Given the following data:

Scientific data:

Vacuum permittivity =

To determine the quantity of energy that is stored by the electric field between two square plates:

First of all, we would determine the area of the square plates.

Mathematically, the quantity of energy that is stored in an electric field between two square plates:

Where:

Substituting the given parameters into the formula, we have;

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answer: 2×10^-2kg

explanation: density= mass per volume

vol=mass/density

converting to s.i units we have;

3÷1000kg = 0.003

1.5÷100m = 0.15

0.003/0.15 = 0.02kg