Two point charges q1 = +5.70 nc and q2 = −2.30 nc are separated by 45.0 cm. (a) what is the electric potential at a point midway between the charges? 111.3 incorrect: your answer is incorrect. seenkey 136 u

Explanation:

It is given that,

Charge,

Charge,

Distance between charges, d = 45 cm = 0.45 m

We need to find the electric potential at a point midway between the charges. It is given by :

Midway between the charges means, r = 22.5 cm = 0.225 m

So, the electric potential at a point midway between the charges is 136 volts. Hence, this is the required solution.

t = 1/400 h   ⇔ 0.0025 h ⇔ 9s ⇔ 0.15 m

any of the answers are correct.

energy stored in the capacitor= 9.72 x 10⁻⁴ j

explanation:

the energy stored in the capacitor is given by

e= 1/2 c v²

e= energy stored

c= capacitance= 1.5 µc= 1.5 x 10⁻⁶f

v= potential difference=36 v

so energy stored= e= 1/2 (1.5 x 10⁻⁶) (36)²

energy stored= 9.72 x 10⁻⁴j