If a particle with a charge of +3.3 × 10? 18 c is attracted to another particle by a force of 2.5 × 10? 8 n, what is the magnitude of the electric field at this location? 8.3 × 10^-26 nc 1.8 × 10^10 nc 1.3 × 10^-10 n/c 7.6 × 10^9 n/c

Explanation:

The relationship between force exerted on a charge and strength of the electric field is given by

where

F is the strength of the electric force

q is the charge of the particle

E is the magnitude of the electric field

For the particle in the problem, we have

So the magnitude of the electric field at the location of the particle is

your answer is c! hope this : )

find the surface area of the sphere to the nearest square unit. use a calculator.

a. 254 in.2

b. 64 in.2

c. 127 in.2

d. 1,018 in.2