Brain burner! you observe a hockey puck of mass 0.13 kg, traveling across the ice at speed 17.4 m/sec. the interaction of the puck and the ice results in a frictional force on the puck, f = 0.15 n. calculate: the stopping distance for this puck. type in the numeric part of your answer to the nearest 0.1 m of stopping distance. e. g., if your answer works out to be 2.337 m, then type 2.3 in the answer box. note: this brain burner calculation puts together

The distance at which the puck of mass 0.13 kg, traveling across the ice at speed 17.4 m/sec will stop is 131.2 meters.

Given to us

Mass of the puck, m = 0.13kg

The velocity of the ice, u = 17.4 m/sec

Friction force, f = 0.15 N

We know we want to stop the puck, therefore, the final velocity of the puck will be 0.

v = 0

We know that according to the first law of motion,

Force = mass x acceleration

F = m x a

Substitute the value,

As we know that the final velocity of the puck will be 0, therefore, there will be a deceleration in the puck.

a = -1.1538 m/s².

Thus, the acceleration of the ice puck is -1.1538 m/s².

We know that according to the third equation of the motion,

substitute the values,

s = 131.2012 = 131.2 meters

Hence, the distance at which the puck of mass 0.13 kg, traveling across the ice at speed 17.4 m/sec will stop is 131.2 meters.

Learn more about Equation of Motion:

link

did yall get answers for this yet