Earth has a mass of 5.97 x 10*kg, and a mean radius of 6.38 x 108m. what would be the orbital speed and period of a satellite in
orbit 1.44 x 109 m above earth?

Explanation:

Centripetal acceleration = acceleration due to gravity

v² / r = GM / r²

Solving for velocity:

v = √(GM / r)

Given:

G = 6.67×10⁻¹¹ m³/kg/s²

M = 5.97×10²⁴ kg

r = 6.38×10⁸ m + 1.44×10⁹ m = 2.078×10⁹ m

v = √(6.67×10⁻¹¹ × 5.97×10²⁴ / 2.078×10⁹)

v = 438 m/s

Period is the time to travel one circumference:

T = 2πr / v

T = 2π (2.078×10⁹) / 438

T = 2.98×10⁷ s

T = 8290 hr

T = 345 days

yup its correct its: c) b b

it is given that trillions of microbes make up to 1% to 3% of the body mass.

let's take average of this percentage: 2%

consider the average mass of the human body as 70 kg.

then, trillions of microbes would have mass  

therefore, 100 trillion micro-organisms would weigh:

this is an approximate value and could change depending on the mass of the human body and percentage of the microbes present in it.

average mass per microorganism =