The voltage between the cathode and the screen of a television set is 30 kv. if we assume a speed of zero for an electron as it leaves the cathode, what is its speed (m/s) just before it hits the screen? 1.48.7 x 10 2.23x 10 3. 10.2x 10 4.5.2x 105 5. 16.2x 10

i don't know that i agree with that but what's the question ?

that would be because of both gravity and friction. so     c

see the picture for the vector

the magnitude of the vector by pythagorean theorem

r = √( (-10)^2 + (3)^2 ) = √109

magnitude = √109 units

the direction angle between vector and x-axis is

tan^(-1)(3/10) = 16.699

so the direction is approximately 16.7 degrees north of west