The position of a 0.30-kg object attached to a spring is described by -(0.25m)cos(0.4xt). find (a) the amplitude of the motion, (b) the spring constant (e) the position of the object at 1 -0.30 s, and (d) the object's speed at 1-0.30 s.

the maxium height is 34m/s

higher potential

explanation:

because it is in a high speed so it must move into a of high potential

pythagoras' theorem

square root (-5^2+9^2)

square root (25+81)

square root (106)

angle is tan^-1(9/5)

neg x, pos y

365.25 earth days are in the year of a light year