What is the capacitance of a parallel place capacitor with plates of area 1.0 cm2 that are separated by a distance of 0.1 mm? assume that strontium titanate is the dielectric.

C = 0.274μF.

The capacitance when a dielectric is present is given by the equation:

C = kε₀(A/d)

Where k is the dielectric constant of the material, ε₀ is a universal constant, A is the area of the capacitor's plates, and d is the distance that separate the plates.

A parallel plates capacitor with plates of area 1.0cm² that are separated by a distance of 0.1mm, the dielectric constant of the stronium titanate is 310 at a temperature of 20 ° C.

K = 310.00, ε₀ = 8.85x10⁻¹²F/m, A = 1.00x10⁻²m², and d = 0.10x10⁻³m. Substituing the values in the equation C = kε₀(A/d):

C = (310.00)(8.85x10⁻¹²F/m)(1.00x10⁻²m²/0.10x10⁻³m)

C = (2.74x10⁻⁹F/m)(100m)

C = 2.74x10⁻⁷F

C = 0.274x10⁻⁶ = 0.274μF

answer: the correct answer id option(d).

explanation:

snell's law refraction:

the angle of refraction =

the angle of incidence =

refractive index of air = = 1

refractive index of glycerol = 1.47

from the given options, the most closest answer to 63.72° is 65° of option (d).

conduction, convection, radiation