Find the brewster angle for light reflected at a water-glass interface. use n = 1.52 for glass. assume incident light in the water.

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explanation:

electrical potential energy =0.072 j

explanation:

electrical potential energy is given by

u= q δv

q= charge=6 c

δv= potential difference and is given by

δv= e d

e= electric field

d= distance=5 mm=0.005 m

δv=2.4 (0.005)=0.012 v

now electric potential energy= u= q δv

u=6 (0.012)

u=0.072 j

the answer you are looking for is d. there are no holes for blood to enter or leave the system. your welcome