Ahuge cannon is assembled on an airless planet having insignificant axial spin. the planet has a radius of 5.00 × 10 6 m and a mass of 4.69 × 10 23 kg . the cannon fires a projectile straight up at 2000 m/s. what is the projectile's speed as it passes an observation satellite located at a height of 1000 km above the surface of the planet ?

this could be newton#'s law of cooling. the cooling curve is exponential

  distance on the y-axis and time on the x-axis.

explanation:

the instantaneous velocity = change in position/time taken

the slope of the graph should give instantaneous velocity.

  slope of a graph = change in value of y -axis / change in values of x -axis

  comparing both the equations

    change in value of y -axis = change in position

  change in values of x -axis = time taken

so position values should be on the y axis and time values should be on the x axis.

distance on the y-axis and time on the x-axis.

we're given that v₀ = 0 and a = 5.4 m/s². therefore, since v = at + v₀ for constant acceleration the equation for velocity is

after 28s,

m/s

which i would round to 150 m/s as my final answer