A1200 kg car traveling north at 14 m/s is rear-ended by a 2000 kg truck traveling at 30 m/s. what is the total momentum before and after the collision?

Total momentum before and after the collision = 76800 kgm/s along north.

Explanation:

Let positive x axis represent east and positive y axis represent north.

Momentum is conserved, that is total momentum before and after the collision are same.

A 1200 kg car traveling north at 14 m/s is rear-ended by a 2000 kg truck traveling at 30 m/s.

That is 1200 kg is moving north at 14 m/s and 2000 kg truck is also moving north at 30 m/s.

Momentum of car = 1200 x 14 j = 16800 j kgm/s

Momentum of truck = 2000 x 30 j = 60000 j kgm/s

Total initial momentum = 16800j + 60000j = 76800 j kgm/s

Total momentum before and after the collision = 76800 kgm/s along north.

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in simple terms, the principle states that the buoyancy force on an object is equal to the weight of the fluid displaced by the object, or the density of the fluid multiplied by the submerged volume times the gravitational acceleration, g. this is also known as upthrust.